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In the binomial expansion of (a - b)^(n)...

In the binomial expansion of `(a - b)^(n) , n ge 5` , the sum of
the ` 5^(th) and 6^(th)` terms is zero. Then, `a//b` equals

A

`(5)/(n-4)`

B

`(6)/(n-5)`

C

`(n-5)/(6)`

D

`(n-4)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • In the binomial expansion of (a-b)^(n), n le 5 the sum of the 5th and 6th terms is zero. Then (a)/(b) equals

    A
    `(n-5)/(6)`
    B
    `(n-4)/(5)`
    C
    `(5)/(n-4)`
    D
    `(6)/(n-5)`

  • In the binomial expansion of (a-b)^(n), n ge5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals:

    A
    `(5)/(n-4)`
    B
    `(6)/(n-5)`
    C
    `(n-5)/(6)`
    D
    `(n-4)/(5)`

  • If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then th e values of a//b =

    A
    `(n-4)/(5)`
    B
    `(2(n-4))/(5)`
    C
    `(5)/(n-4)`
    D
    `(5)/(2(n-4))`

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