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On a frictionless surface, a ball of mas...

On a frictionless surface, a ball of mass m moving at a speed v makes a head on collision with an identical ball at rest. The kinetic energy of the balls after the collision is 3/4th of the original. Find the coefficient of restitution.

Text Solution

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As we have seen in the above discussion, that under the given conditions :

By using conservation of linear momentum and equation of e, we get,
`v_(1)'=((1+e)/(2))v and v_(2)'=((1-e)/(2))v`
Given that `K_(f)=(3)/(4)K_(1)`
or `(1)/(2)mv'_(1)^(2)+(1)/(2)mv'_(2)^(2)=(3)/(4)((1)/(2)mv^(2))`
Substituting the value, we get
`((1+e)/(2))^(2)+((1-e)/(2))^(2)=(3)/(4)`
or `e=(1)/(sqrt(2))`
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Knowledge Check

  • Choose the most appropriate option. A ball of mass m moving at a speed v makes a head on collision with an identical ball at rest. The kinetic energy at the balls after the collision is 3/4th of the original. What is the coefficient of restitution?

    A
    `1//sqrt(3)`
    B
    `1//sqrt(2)`
    C
    `sqrt(2)`
    D
    `sqrt(3)`
  • A ball of mass m moving with a speed v makes a head on collision with an identical ball at rest. The kinetic energy after collision of the balls is three fourth of the original kinetic energy. The coefficient of restitution is

    A
    `1/2`
    B
    `1/3`
    C
    `1/(sqrt2)`
    D
    `1/(sqrt3)`
  • A ball of 4 kg mass moving with a speed of 3ms^(-1) has a head on elastic collision with a 6 kg mass initially at rest. The speeds of both the bodies after collision are respectively

    A
    `0.6 ms^(-1), 2.4 ms^(-1)`
    B
    `-0.6 ms^(-1), -2.4 ms^(-1)`
    C
    `-0.6 ms^(-1), 2.4 ms^(-1)`
    D
    `-0.6 ms^(-1), -2.4 ms^(-1)`
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