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Two blocks of masses m(1) and m(2) are c...

Two blocks of masses `m_(1)` and `m_(2)` are connected by a massless spring and placed on smooth surface. The spring initially stretched and released. Then :

A

the momentum of each particle remains constant separately

B

the magnitude of momentums of each body are equal to each other

C

the mechanical energy of system remains constant

D

both (C) and (B) are correct

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Two block of masses m1 and m2 are connected with a massless unstretched spring and placed over a plank moving with an acceleration 'a' as shown in figure. The coefficient of friction between the blocks and platform is mu

    A
    spring will be stretched if `a gt mug `
    B
    spring will be commpressed if `a le mug`
    C
    spring will neither be compressed nor be stretched for `a lt mug` only.
    D
    spring will be in its natural length under all conditions.

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    A
    `F=mu(m_(1)+(m_(2))/(2))g`
    B
    `F=mu((m_(1))/(2)+m_(2))g`
    C
    `F=mu(m_(1)^(2)+(m_(2)^(2))/(2))g`
    D
    `F=mu^(2)(m_(1)^(2)+(m_(2))/(2))g`

  • Two blocks of masses m_(1) =1kg and m_(2) = 2kg are connected by a spring of spring constant k = 24 N/m and placed on a frictionless horizontal surface. The block m_(1) is imparted an initial velocity v_(0) = 12cm/s to the right. The amplitude of osciallation is

    A
    2 cm
    B
    1 cm
    C
    3 cm
    D
    4 cm

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