Prove by the principle of mathematical induction that for all `n in N :` `1^2+2^2+3^2++n^2=1/6n(n+1)(2n+1)`

Explanation

Given,

P(n)=`1^2+2^2+3^2++n^2=1/6n(n+1)(2n+1)`

For n=1

=`1^2=1`

P(n) is true

P(k):

`1^2+2^2+3^2+........+k^2=(k(k+1)(2k+1)​)/6`


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