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When two soap bubbles of radius r(1) " a...

When two soap bubbles of radius `r_(1) " and " r_(2)(r_(2) gt r_(1))` coalesce, the radius of curvature of common surface is

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`:'r_(1)ltr_(2)`
`:.P_(1)gtR_(2)` Small portion of bubbles is in contact and in equilibrium

`P_(1)-P_(2)=(4T)/(r)implies(4T)/(r_(1))-(4T)/(r_(2))impliesr=(r_(1)r_(2))/(r_(2)-r_(1))`
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Knowledge Check

  • Two soap bubbles each of radius r are touching each other. The radius of curvature of the common surface will be:

    A
    infinite
    B
    2r
    C
    `r`
    D
    `r//2`

  • If two bubble of radii 0.03 cm and 0.04 cm come in contact with each other then the radius of curvature of the common surface 'r' is given by.

    A
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    B
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    C
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    D
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  • A soap bubble of radius r_(1) is placed on another soap bubble of radius r_(2)(r_(1) lt r_(2)) . The radius R of the soapy film separating the two bubbles is :

    A
    `r_(1) + r_(2)`
    B
    `sqrt(r_(1)^(2) + r_(2)^(2))`
    C
    `(r_(1)^(3) + r_(2)^(3))`
    D
    `(r_(2)r_(1))/(r_(2) - r_(1))`

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