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A(a, b) and B(0, 0) are two fixed points...

A(a, b) and B(0, 0) are two fixed points. `M_(1)` is the mid point of AB. `M_(2)` is the midpoint of `bar(AM_(1)), M_(3)` is the midpoint of `bar(AM_(2))` and so on. Then `M_(5)` is

A

`((7a)/(8), (7b )/(8))`

B

`((15a)/(16), (15b)/(16))`

C

`((31b)/(32), (31b)/(32))`

D

`((63a)/(64), (63b)/(64))`

Text Solution

Verified by Experts

The correct Answer is:
C
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