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The equation of the circle with centre (...

The equation of the circle with centre (3, -2) and radius 3 is

A

`x^(2)+y^(2)-6x+4y+4=0`

B

`x^(2)+y^(2)-4x+6y+9=0`

C

`x^(2)+y^(2)+14x+6y-42=0`

D

`x^(2)+y^(2)+2x+16y+40=0`

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A
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Find the equation of the circle with centre (-3,2) and radius 4 .

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Knowledge Check

  • The equatinn of the circle with centre origin and radius 2 is

    A
    `x^(2)+y^(2)-6x+4y+4=0`
    B
    `x^(2)+y^(2)=4`
    C
    `x^(2)+y^(2)-4x+6y-12=0`
    D
    `x^(2)+y^(2)+2x+16y+40=0`

  • The polar equation of the circle with centre (2, (pi)/(2)) and radius 3 units is

    A
    `r^(2) + 4 r cos theta = 5`
    B
    `r^(2) + 4 r sin theta = 5`
    C
    `r^(2) - 4 r sin theta = 5`
    D
    `r^(2) - 4r cos theta = 5`

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    In each of the following find the equation of the circle with centre (-2,3) and radius 4

    In each of the following find the equation of the circle with centre (-a, -b) and radius sqrt(a^(2)-b^(2))

    Find the equation of the circle with centre at (0,0) and radius r .

    In each of the following find the equation of the circle with centre (1,1) and radius sqrt(2)

    The circle with centre (3/2,1/2) and radius sqrt(3/2) is

    The equation of the circle with centre (3,2) and the power of (1,-2) w.r.t the circle x^(2)+y^(2)=1 , as radius is

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