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The trajectory of a projectile fired hor...

The trajectory of a projectile fired horizontally with velocity u is parabola given by-

A

`y=(g)/(2u^(2))x^(2)`

B

`y=-(g)/(2u^(2))x^(2)`

C

`y=(g)/(2u^(2))y^(2)`

D

`y=(g)/(2u^(2))y^(2)`

Text Solution

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The correct Answer is:
B
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Trajectory Of Horizontal Projectile

A projectile is projected from horizontal with velocity (u) making an angle 45^(@) with the horizontal direction. Find the distance of the highest point of the projectile from its starting point.

Knowledge Check

  • At the top of the trajectory of a projectile, the directions of its velocity and acceleration are

    A
    Perpendicular to each other
    B
    Parallel to each other
    C
    Inclined to each other at an angle of `45^(@)`
    D
    Antiparallel to each other

  • At the top of the trajectory of projectile the

    A
    Acceleration is minimum
    B
    Velocity is zero
    C
    Acceleration is maximum
    D
    Acceleration is g

  • a projectile is fired from the surface of the earth with a velocity of 5ms^(-1) and angle theta with the horizontal. Another projectile fired from another planet with a velocity of 3ms^(-1) at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in ms^(-2) is given (g=9.8 ms^(-2))

    A
    `3.5`
    B
    `5.9`
    C
    `16.3`
    D
    `110.8`

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