A ray of light is incident on a transparent glass slab of refractive index 1.62. If the reflected and refracted rays are mutually perpendicular, what is the angle of incidence ? [`tan^(–1) (1.62) = 58.3^(@)`]

Explanation

To solve the problem step by step, we will use the principles of optics, specifically the laws of reflection and refraction.

### Step 1: Understanding the Problem
We have a ray of light incident on a glass slab with a refractive index (μ) of 1.62. The reflected ray and the refracted ray are mutually perpendicular, meaning they form a right angle (90 degrees) with each other.

### Step 2: Setting Up the Angles
Let:
- \( I \) = angle of incidence
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