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CH(3)NH(2)(0.1"mole",K(b)=5xx10^(-4)) i...

`CH_(3)NH_(2)(0.1"mole",K_(b)=5xx10^(-4))` is added to 0.08 moles of HCI and the solution is diluted to one litre. The resulting hydrogen ion concentration is

A

`1.6 xx 10^(-11)`

B

`8 xx 10^(-11)`

C

`5 xx 10^(-5)`

D

`2 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • HH_(3)NH_(2)(0.1"mole",K_(b)=5xx10^(-4)) is added to 0.08 moles of HCI and the solution is diluted to one litre. The resulting hydrogen ion concentration is

    A
    `1.6xx10^(-11)`
    B
    `8xx10^(-11)`
    C
    `5xx10^(-5)`
    D
    `8xx10^(-2)`

  • 0.1 mole of CH_(3)NH_(2)(K_(b)=5xx10^(-4)) is added to 0.08 mole of HCl and the solution is diluted to one litre. The resulting [H^(+)] is

    A
    `1.6xx10^(-11)`
    B
    `8xx10^(-11)`
    C
    `5xx10^(-5)`
    D
    `8xx10^(-2)`

  • 0.1 mole of CH_(3)NH_(2)(K_(b)=5xx10^(-4)) is mixed with 0.08 mole of HCl and the solution diluted to one litre. The H^(+) ion concentration in the solution will be

    A
    `1.6xx10^(-11)`
    B
    `8xx10^(-11)`
    C
    `5xx10^(-5)`
    D
    `8xx10^(-2)`

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