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Automobile air bags are inflated with N(...

Automobile air bags are inflated with `N_(2)` gas which is formed by the decomposition of solid sodium azide `( NaN_(3))`. The other product is Na-metal.Calculate the volume of `N_(2)` gas at `27^(@)C` and 756 Torr formed by the decomposition of 125 gm of solid azide.

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71.4L
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Knowledge Check

  • The compound(s) which generate (s) N_(2) , gas upon thermal decomposition below 300^(@)C is (are)

    A
    `NH_(4)NO_(3)`
    B
    `(NH_(4))_(2)Cr_(2)O_(7)`
    C
    `Ba(N_(3))_(2)`
    D
    `Mg_(3)N_(2)`

  • The compound(s) which generate(s) N_(2) gas upon thermal decomposition below 300^(@)C is (are)

    A
    `NH_(4)NO_(3)`
    B
    `(NH_(4))_(2)Cr_(2)O_(7)`
    C
    `Ba(N_(3))_(2)`
    D
    `Mg_(3)N_(2)`

  • The compound(s) which generate(s) N_(2) gas upon thermal decomposition below 300^(@)C is (are)

    A
    `NH_(4)NO_(3)`
    B
    `(NH_(4))_(2)Cr_(2)O_(7)`
    C
    `Ba(N_(3))_(2)`
    D
    `Mg_(3)N_(2)`

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    34 gm of ammonia on decomposition gives some hydrogen gas along with N_(2) gas. Hydrogen underwent combustion with oxygen gas and water wa formed. Calculate number of drops of water formed if each drop contain 6 ml of water.

    60 mL of a mixture of nitrous oxide and nitric oxide was exploded with excess of hydrogen. If 38 mL of N_(2) was formed, calculate the volume of each gas in the mixture.

    What total volume , in litre at 627^(@) C and 0.821 atm, could be formed by the decomposition of 16 gm of NH_(3)NO_(3) ?Reaction : 2NH_(4)NO_(3) to 2N_(2) + O_(2) + 4H_(2)O_((g)) .

    The compounds (s) which generated (s) N_2 gas upon thermal decomposition below 300^(@)C is (are)

    Specific surface area of a solid adsorbent is the surface area of the unit mass of the adsorbent. For any adsorbent, the specific surface area may be increased by taking the adsorbent in powdered form or by increasing the pores in the solid. 112 cm^(3) hydrogen gas is adsorbed uniformly at the surface of 5 gm palladium at 273^(@)C and 2 atm. If the effective surface area of each hydrogen molecule is 0.4 nm^(2) , then the specific surface area of palladium is : [Take : N_(A) = 6x10^(23) ]

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