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The general solution of the trigonometri...

The general solution of the trigonometric equation `sinx+cosx=1` is given by `x=2npi,n0,+-1,+-2` `x=2npi+pi/2; n=0,+-1,+-2, dot` `x=npi+(-1)^npi/4-pi/4n=0,+-1,+-2, ` `non eoft h e s e`

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`sinx+cosx=1`
`sinx=1-cosx`
`1-sinx=sqrt(1-sin^2x)`
`(1-sinx)^2=(1-sin^2x)`
`1+sin^2x-2sinx=1-sin^2x`
`2sin^2x-2sinx=0`
`2sinx(sinx-1)=0`
`sinx=0`
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The general solution ofthe trigonometrical equation sinx+cosx=1 for n=0, +- 1, +-1 is given by (a) x=2npi (b) x=2npi+pi/2 (c) x=npi+(-1)^npi/4-pi/4 (d) non of these

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  • The general solution of the trigonometrical equation sin x + cosx = 1 , for n = 0 ,pm 1 , pm 2,. …….. is given by

    A
    `x = 2npi`
    B
    `x = 2n pi+ 1/2 pi`
    C
    `x = npi +(-1)^n (pi//4) - pi//4`
    D
    None of these
  • The general solution of the equation (1-sin x+….+(-1)^(n)sin^(n)x+…)/(1+sinx+….+sin^(n)x+…)=(1-cos2x)/(1+cos2x), x pi (2n+1) pi//2, n in I is

    A
    `(-1)^(n)(pi//3)+n pi`
    B
    `(-1)^(n)(pi//6)+n pi`
    C
    `(-1)^(n+1)(pi//6)+n pi`
    D
    `(-1)^(n-1)(pi//3)+n pi, (n in I)`
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