If `secx+sec^2x=1` then the value of `tan^8x-tan^4x-2tan^2x+1` will be equal to 0 (b) 1 (c) 2 (d) 3

Explanation

To solve the equation \( \sec x + \sec^2 x = 1 \) and find the value of \( \tan^8 x - \tan^4 x - 2\tan^2 x + 1 \), we will follow these steps:

### Step 1: Rewrite the equation in terms of \( \sec x \)

Given:
\[ \sec x + \sec^2 x = 1 \]
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