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The area of cross-section, length and de...

The area of cross-section, length and density of a piece of a metal of atomic weight `60` are `10^-6 m^2`, `1.0 m` and `5xx10^3 kg//m^3` respectively,every atom contributes one free electron. (Given Avogadro number `=6xx10^23//mol)`. Find the drift velocity of electrons in the metal when the current of `16A` passes through:

Text Solution

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`5xx10^(28//m^(3)),2xx10^(-3)m//s`
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A current of 5 ampere is passing through a metallic wire of cross-section area 4 xx 10^-6 m^2 . If the density of the charge carries in the wire is 5 xx 10^26 m^3 , find the drift speed of the electrons. (b) In copper there are 10^22 free electrons per c.c. , all of which contribute to a current of 1 ampere in a wire of copper of 0.01 cm^2 cross-sectional area : (i) What is the average speed of electrons in the copper ? (ii) What is the electric field in the wire ? Given specific resistance of copper 1.6 xx 10^-8 ohm-meter . ( c) The area of cross-section, length and density of a piece of a metal of atomic weight 60 are 10^-6 m^2, 1.0 m and 5 xx 10^3 kg//m^3 respectively. Find the number of free electrons per unit volume if every atom contributes one free electron. Also, find the drift velocity of electrons in the metal when a current of 16 A passes through it. (Given : Avogadro number 6 xx 10^26//kg-"mole" ).

Electron density in a conductor of area of cross section 0.006 cm^2 is 8.0 xx10^(22) cm ^(-3) . Calculate the drift velocity of electron in the wire if a current of 2 flows through it.

Knowledge Check

  • A current of 10 A is maintained in a conductor of cross-section 1 cm^(2) . If the free electron density in the conductor is 9 xx 10^(28) m^(-3) , then drift velocity of free electrons is

    A
    `6.94 xx 10^(-6) m //s `
    B
    ` 5.94 xx 10^(-2) m //s `
    C
    ` 1.94 xx 10^(-3) m//s `
    D
    ` 2.94 xx 10^(-4) m//s `
  • A current of 10 A is mainatained in a conductor of cross - section 1 cm^(2) . If the free electron density in the conductor is 9 xx 10^(28) m^(-3) , then drift velocity of free electrons is .

    A
    ` 6.94 xx 10^(-6) m//s`
    B
    `5.94 xx 10 ^(-2) m//s`
    C
    `1.94 xx 10^(-3) m//s`
    D
    `2.94 xx 10^(-4) m//s`
  • There is a current of 40 A in a wire 10^(-6)m^(2) area of cross-section. If the number of free electrons per cubic metre is 10^(29) , then the drift velocity is :

    A
    `250xx10^(-3)m//sec`
    B
    `25.0xx10^(-3)m//sec`
    C
    `2.50xx10^(-3)m//sec`
    D
    `1.25xx10^(-3)m//sec`
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