The current I through a rod of a certain...

The current `I` through a rod of a certain metallic oxide is given by `I=0.2 V^(5//2)`, where `V` is the potential difference across it. The rod is connected in series with a resistance to a `6V` battery of negligible internal resistance. What value should the series resistance have so that:
(i) the current in the circuit is `0.44`
(ii) the power dissipated in the rod is twice that dissipated in the resistance.

Verified by Experts

(i) 10.52 `Omega` , (ii) 0.3125`Omega`

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A 3 volt battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

`1A`

1.5A

`2A`

`1//3 A`

`19 Omega`

`17 Omega`

`10 Omega`

`12 Omega`

`5 xx 10^(-5)V//mm`

`2.5 xx 10^(-4)V//cm`

`0.62 xx 10^(-4)V//mm`

`1 xx 10^(-5)V//mm`