Find the area of the smaller region bounded by the ellipse `(x^2)/9+(y^2)/4=1` and the line `x/3+y/2=1`

Explanation

To find the area of the smaller region bounded by the ellipse \(\frac{x^2}{9} + \frac{y^2}{4} = 1\) and the line \(\frac{x}{3} + \frac{y}{2} = 1\), we will follow these steps:

### Step 1: Identify the parameters of the ellipse
The given ellipse is in the standard form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a^2 = 9\) and \(b^2 = 4\). Thus, we have:
- \(a = 3\)
- \(b = 2\)

### Step 2: Calculate the area of the ellipse
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