`(2cos 40^0-cos 20^0)/(sin 20^0)=`

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))=?

What is the value of (cos 40^@ -cos 140^@)//(sin 80^@ + sin 20^@) ?

Evaluate each of the following: (a) cos(40^0-theta)-sin(50^0+theta)+(cos^2 40^0+cos^2 50^0)/(sin^2 40^0+sin^2 50^0) (b) (cos70^0)/(sin20^0)+(cos55^0cos e c35^0)/(tan5^0tan25^0tan45^0tan65^0tan85^0) (c) 2((cos58^0)/(sin32^0))-sqrt(3)((cos38^0cos e c52^0)/(tan15^0tan60^0t a n75^0))

Evaluate : (sin50^0)/(cos40^0)+(cos e c40^0)/(sec50^0)-4cos50^0cos e c40^0

Show that sin70^(0)cos10^(0)-cos70^(0)sin10^(0)=(sqrt(3))/(2)

sin20^(@)*cos40^(@)+cos20^(@)*sin40^(@)=(sqrt(3))/(2)

What is the vlaue of (cos40^(@) - cos140^(@))//(sin80^(@)+sin20^(@))

What is the value of ((cos40^(@)-cos140^(@)))/((sin80^(@)+sin20^(@))) ?