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A point at the periphery of a disc rotat...

A point at the periphery of a disc rotating about a fixed axis moves so that its speed varies with time as `v = 2 t^2 m//s` The tangential acceleration of the point at t= 1s is

A

`4m //s^2`

B

`2sqrt2m //s`

C

`sqrt2 m//s^2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`a_(t)=(dv)/(dt)=4t=4m//s^(2)" at t"=1sec`
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