Home
Class 12
PHYSICS
A projectile is projected with a velocit...

A projectile is projected with a velocity u at an angle `theta` with the horizontal. For a fixed `theta`, which of the graphs shown in the following figure shows the variation of range R versus u?

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the variation of range \( R \) versus initial velocity \( u \) for a projectile launched at a fixed angle \( \theta \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Range Formula**: The range \( R \) of a projectile launched with an initial velocity \( u \) at an angle \( \theta \) is given by the formula: \[ R = \frac{u^2 \sin(2\theta)}{g} \] where \( g \) is the acceleration due to gravity. 2. **Identifying Fixed Parameters**: In this scenario, the angle \( \theta \) is fixed. This means that \( \sin(2\theta) \) is a constant value for a given \( \theta \). Therefore, we can denote this constant as \( k = \sin(2\theta) \). 3. **Rewriting the Range Formula**: Substituting \( k \) into the range formula, we get: \[ R = \frac{u^2 k}{g} \] This shows that the range \( R \) is directly proportional to the square of the initial velocity \( u \). 4. **Establishing the Relationship**: Since \( R \) is proportional to \( u^2 \), we can express this relationship as: \[ R \propto u^2 \] This indicates that as \( u \) increases, \( R \) increases with the square of \( u \). 5. **Graphical Representation**: The relationship \( R \propto u^2 \) suggests that if we plot \( R \) on the y-axis and \( u \) on the x-axis, the graph will be a parabola opening upwards. The general form of the equation for such a graph is: \[ R = k' u^2 \] where \( k' \) is a constant. 6. **Identifying the Correct Graph**: Among the options provided, the graph that represents a quadratic relationship (a parabola) is the one that shows \( R \) increasing as \( u^2 \). Therefore, the correct option is the one that resembles the shape of a parabola. ### Conclusion: The graph that shows the variation of range \( R \) versus initial velocity \( u \) is a parabola, confirming that \( R \) is proportional to \( u^2 \).

To solve the problem of determining the variation of range \( R \) versus initial velocity \( u \) for a projectile launched at a fixed angle \( \theta \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Range Formula**: The range \( R \) of a projectile launched with an initial velocity \( u \) at an angle \( \theta \) is given by the formula: \[ R = \frac{u^2 \sin(2\theta)}{g} ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

For a projectile first with velocity u at an angle theta with the horizontal.

A projectile is projected with velocity u making angle theta with horizontal direction, find : time of flight.

Knowledge Check

  • A particle is projected with a velocity u making an angle theta with the horizontal. The instantaneous power of the gravitational force

    A
    (a) Varies linearly with time
    B
    (b) Is constant throughout
    C
    (c) Is negative for complete path
    D
    (d) None of the above
  • A projectile is projected with a velocity v_(0) at an angle theta with the horizontal as shown in figure. The angular momentum of particle about the origin:

    A
    is zero when particle is at the origin
    B
    is `(-mv^(3) sin^(2) theta cos theta)/(2g) hatk` when particle is at the highest point of trajectory
    C
    is `(-2mv^(2) sin^(2) theta cos theta)/g hatk` when particle is just about to hit ground
    D
    downward force of gravity exerts a torque in `-z` direction.
  • A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

    A
    `(u cos theta)/(2)`
    B
    `u cos theta`
    C
    `u (2 cos (theta)/(2) - sec (theta)/(2))`
    D
    `u (cos(theta)/(2) - sec(theta)/(2))`
  • Similar Questions

    Explore conceptually related problems

    A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.

    A projectile is fired with a velocity 'u' making an angle theta with the horizontal. Show that its trajectory is a parabola.

    A particle is projected with velocity u at angle theta with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.

    A projectile is fired with a velocity u making an angle theta with the horizontal. What is the magnitude of change in velocity when it is at the highest point

    A projectile is projected with speed u at an angle theta with the horizontal . The average velocity of the projectile between the instants it crosses the same level is