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The efficiency of a Carnot engine is 1/2...

The efficiency of a Carnot engine is 1/2. If the sink temperature is reduced by `100^@ C` , then engine efficiency becomes 2/3. Find the source temperature and sink temperature.

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To solve the problem, we need to find the source temperature (T1) and the sink temperature (T2) of a Carnot engine given its efficiencies at two different conditions. ### Step-by-Step Solution: 1. **Understanding the Efficiency of a Carnot Engine**: The efficiency (η) of a Carnot engine is given by the formula: \[ \eta = 1 - \frac{T_2}{T_1} ...
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The efficiency of Carnots engine ata particular source and sink temperature is 1/2 . When the sink temperature is reduced by 100^@C , the engine efficiency becomes 2/3 . Find the source temperature.

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Knowledge Check

  • The efficiency of a carnot engine depends on the temperature of-

    A
    Source only
    B
    Working substance
    C
    Sink only,
    D
    Source and sink.
  • The efficiency of a Carnot's engine at a particular source and sink temperature is (1)/(2) .When the sink temperature is reduced by 100^(@)C , the engine efficiency, becomes (2)/(3) . Find the source temperature.

    A
    600K
    B
    300K
    C
    500K
    D
    550K
  • The efficiency of a carnot engine is (1)/(6) . If the temperature of the sink is reduced by 62 K, the efficiency becomes (1)/(3) . The temperature of the source and the sink in the first case are respectively.

    A
    372 K, 290 K
    B
    372 K, 310 K
    C
    744 K, 310 K
    D
    744 K, 290 K
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    The efficiency of the carnot engine is (1)/(6) . On decreasing the temperature of the sink by 65 K, the efficiency increases to (1)/(3) . Find the temperatures of the source and the sink.

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