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For a p-V plot, the slope of an adiabati...

For a p-V plot, the slope of an adiabatic curve = x × slope of isothermal at the same point. Here x is :

A

`R/(lamda - 1)`

B

`1/lamda`

C

`lamda`

D

`1/(lamda-1)`

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To find the value of \( x \) in the relationship between the slopes of the adiabatic and isothermal curves on a p-V plot, we can follow these steps: ### Step 1: Understand the Isothermal Process In an isothermal process, the temperature remains constant. The equation governing this process is given by: \[ PV = \text{constant} \] Differentiating this equation with respect to volume \( V \) gives us: \[ d(PV) = 0 \implies P \, dV + V \, dP = 0 \] Rearranging this, we find: \[ \frac{dP}{dV} = -\frac{P}{V} \] This expression represents the slope of the isothermal curve. ### Step 2: Understand the Adiabatic Process In an adiabatic process, there is no heat exchange with the surroundings. The relationship for an adiabatic process is given by: \[ PV^\lambda = \text{constant} \] where \( \lambda \) is the adiabatic constant. Differentiating this equation gives: \[ d(PV^\lambda) = 0 \implies V^\lambda \, dP + P \lambda V^{\lambda - 1} \, dV = 0 \] Rearranging this leads to: \[ \frac{dP}{dV} = -\frac{\lambda P}{V} \] This expression represents the slope of the adiabatic curve. ### Step 3: Relate the Slopes of the Two Processes From the expressions derived, we have: - Slope of isothermal process: \( \frac{dP}{dV} = -\frac{P}{V} \) - Slope of adiabatic process: \( \frac{dP}{dV} = -\frac{\lambda P}{V} \) ### Step 4: Set Up the Relationship We can set the slopes of the two processes equal to each other in the form: \[ \text{slope of adiabatic} = x \times \text{slope of isothermal} \] Substituting the expressions we derived: \[ -\frac{\lambda P}{V} = x \left(-\frac{P}{V}\right) \] ### Step 5: Solve for \( x \) Cancelling the common terms \( -\frac{P}{V} \) from both sides (assuming \( P \) and \( V \) are not zero): \[ \lambda = x \] Thus, we find that: \[ x = \lambda \] ### Final Answer The value of \( x \) is equal to \( \lambda \), the adiabatic constant. ---

To find the value of \( x \) in the relationship between the slopes of the adiabatic and isothermal curves on a p-V plot, we can follow these steps: ### Step 1: Understand the Isothermal Process In an isothermal process, the temperature remains constant. The equation governing this process is given by: \[ PV = \text{constant} \] Differentiating this equation with respect to volume \( V \) gives us: ...
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Knowledge Check

  • In a p-V diagram for an ideal gas (Where , p is along y-axis and V is along X- axis) , the value of the ratio "slope pof adiabatic curve/ Slope of the isothermal curve"at any point will be (Where symbols have their usual meanings ).

    A
    1
    B
    2
    C
    `C_(p)//C_(v)`
    D
    `C_(v)//C_(p)`
  • The slope of isothermal and adiabatic curves are related as

    A
    isothermal curve slope = adiabatic curve slope
    B
    isothermal curve slope = `gamma xx `adiabatic slope
    C
    adiabatic curve slope = `gamma xx ` isothermal slope
    D
    adiabatic curve slope = (1/2) `xx` isothermal curve slope
  • Slope of normal to the curve y=x^2-x and x=2 is

    A
    `-1/3`
    B
    `-1/7`
    C
    `-1/9`
    D
    `-1/11`
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