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Acceleration of a particle is given by ...

Acceleration of a particle is given by
a = 2x
(i) It’s velocity at position x. Given that v = 10 m/s when x = 0.
(ii) Minimum speed that the particle can attain

Text Solution

AI Generated Solution

To solve the problem step by step, we will derive the velocity of the particle as a function of position \( x \) and then determine the minimum speed that the particle can attain. ### Step 1: Relate acceleration to velocity and position Given that the acceleration \( a \) of the particle is expressed as: \[ a = 2x \] We know that acceleration can also be expressed in terms of velocity \( v \) and position \( x \) using the chain rule: ...
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Knowledge Check

  • If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

    A
    0
    B
    2
    C
    4
    D
    8

  • Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

    A
    `18 ms^(-2)`
    B
    `12 ms^(-2)`
    C
    `15 ms^(-2)`
    D
    zero

  • If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

    A
    `(7)/(2)m//s`
    B
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    C
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