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The energy of an electron in the 3rd orb...

The energy of an electron in the 3rd orbit of H- atom ( in J ) is approximately.

A

`-2.18xx10^(-18)`

B

`-2.42xx10^(-19)`

C

`-1.21xx10^(-19)`

D

`-3.63xx10^(-19)`

Text Solution

Verified by Experts

The correct Answer is:
B

For electron in 3rd orbit of H-atom.
Energy `=-(2pi^(2)mk^(2)e^(4))/(n^(2)h^(2))`
Substituting the standard values, we get Energy
`=-(-2xx((22)/(7))^(2)xx9.1xx10^(-31)xx(9xx10^(9))^(2)xx(1.6xx10^(-19))^(4))/((6.6xx10^(-34))^(2)xx(3)^(2))`
`=(-2xx3.14xx3.14xx9.1xx9xx9xx(1.6xx1.6)^(2)xx10^(-31+18-76))/(9xx6.6xx6.6xx10^(-68))`
`=-2.42xx10^(-19)" J"`
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Knowledge Check

  • Energy of an electron in nth Bohr orbit is given as

    A
    `-(n^2 h^2)/(4pi^2 mZe^2)`
    B
    `-(2pi^2 Z^2 me^4)/(n^2 h^2)`
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    `-4.2 eV`
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    `-6.8 eV`
    D
    `+6.8 eV`
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    `-(n^(2)h^(2))/(4pi^(2)mZe^(2))`
    B
    `-(2pi^(2)Z^(2)me^(4))/(n^(2)h^(2))`
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