The following reaction occurs in acidic medium
`KMnP_(4) + 8 H^(+) 5e^(-) to K^(+) Mn^(2+) + 4H_(2) O`
what is the equivalent weight of `KMnO_(4)`?
[Molecular weight of `KMnO_(4) = 158`]

Options

A. 79
B. 31.6
C. 158
D. 39.5

Answer

b

Explanation

In the reaction (in acidic medium)
`KmnO_(4) + 8H^(+) + 5e^(-) to K^(+) Mn^(2+) + 4H_(2) O` `KMnO_4)` gain5 electrons from reductant.
`:.` Equvalent weight of `KMnO_(4) = (158)/(5)`
= 31.6 (in g/equivalent