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18 g of glucose is dissolved in 90 g of ...

18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure of the solution is equal to

A

6.1

B

0.2

C

5.1

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
(d)
Relative lowering of vapour pressure`((p_(1)^(0)-P_(s))/(P^(0)))`
= `("No of moles of solvent")/(" No of moles of solute")`
`(18/180)/(90/18)`
= `(1)/(10)xx(1)/(5)`
= `0.02`
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Knowledge Check

  • The relative lowering of vapour pressure is equal to

    A
    Ratio of the number solute molecules to the totalnumber of molecules in solution
    B
    Ratio of the number of solvent molecules to the number of solute molecules
    C
    Ratio of the number of solute molecules to the number of solvent molecules
    D
    Ratio of the number of solvent molecules to the total number of molecules in solution

  • Relative lowering of vapour pressure is maximum for

    A
    0.1 m urea
    B
    0.1 m NaCl
    C
    0.1 m `MgCl_2`
    D
    0.1 m `Al_2(SO_4)_3`

  • 6 g of urea is dissolved in 90g of boiling water. The vapour pressure of the solution is

    A
    744.8 mm
    B
    758 mm
    C
    761 mm
    D
    760 mm

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