18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure of the solution is equal to

Options

A. 6.1
B. 0.2
C. 5.1
D. 0.02

Answer

(d)

Explanation

Relative lowering of vapour pressure`((p_(1)^(0)-P_(s))/(P^(0)))`
= `("No of moles of solvent")/(" No of moles of solute")`
`(18/180)/(90/18)`
= `(1)/(10)xx(1)/(5)`
= `0.02`