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Henry's law constant for CO2 in water is...

Henry's law constant for `CO_2` in water is 1.67 kbar at `25^@ C`. The quantity of `CO_2` in 1000 mL of soda water when packed under 5 bar `CO_2` pressure at `25^@ C` is

A

0.084 mol

B

0.167 mol

C

0.252 mol

D

0.336 mol

Text Solution

Verified by Experts

The correct Answer is:
B
Given,
Pressure of ` CO_2 = 5 ` bar
`(P)= 5 xx 10^5 ` Pa
` K_H = 1.67 xx 10^8 ` Pa
From Henry's law `P= K_H = (5xx 10^5)/(1.67 xx 10^8)`
`rArr X = 2.99 xx 10^(-3)`
Volume of water (soda water) `= 1000 ml`
Density of water = 1 g/ml
Mass = Volume `xx` density.
So 1000 ml of water = 1000 g of water
Molar mass of water `(H_2 O)= 18 g //ml.`
Number of moles of water `(H_2 O) = ("Mass")/("Molar water")= (1000)/(18) = 55.55 ml ` of water
Mole fraction `= (n^(co_2))/(n_(co_2) + n_(H_2 O))`
`2.99 xx 10^(-3) = (n_(co_2) )/(55.55)`
`n_(co_2) = 0.167` mol
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Knowledge Check

  • Henry' s law constant for CO_(2) in water is 1.67 K bar at 25^(@)C. The quantity of CO_(2) in 1000 mL of soda water when packed under 5 bar CO_(2) pressure at 23^(@)C is

    A
    0.084
    B
    0.167 mol
    C
    0.252 mol
    D
    0.336 mol

  • The quantity of CO_(2) in 500 mL of soda water when packed under 3.34 bar CO_(2) pressure at 298 K in g is

    A
    2.442
    B
    1.221
    C
    4.884
    D
    3.663

  • The quantity of CO_2 in 500ml of soda water when packed under 2.5 atm CO_2 pressure at 298 k is....... gm (Henry's law constant 1.67 xx 10^8 pa at 298K)

    A
    0.64
    B
    1.86
    C
    6.4
    D
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