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"cos " pi/7 - "cos " (2pi)/7 + "cos" (3p...

`"cos " pi/7 - "cos " (2pi)/7 + "cos" (3pi)/7 - "cos" (4pi)/7 + "cos "(5pi)/7 - "cos"(6pi)/7` =

A

0

B

`3/2`

C

`3/4`

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
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