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If m is the slop of the normal to the c...

If m is the slop of the normal to the continous curve `y=f(x)` at the point `(x_(1),y_(1))`, then m is equal to-

A

`((dy)/(dx))_((x_(1),y_(1))`

B

`(-(dy)/(dx))_((x_(1),y_(1))`

C

`((dx)/(dy))_((x_(1),y_(1))`

D

`(-(dx)/(dy))_((x_(1),y_(1))`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • The eqaution of the normal to the continuous curve y=f(x) at the point (x_(1),y_(1)) is-

    A
    `y-y_(1)=-(dx)/(dy)(x-x_(1))`
    B
    `x-x_(1)=-(dx)/(dy)(y-y_(1))`
    C
    `y-y_(1)=-(dy)/(dx)(x-x_(1))`
    D
    `x-x_(1)=-(dy)/(dx)(y-y_(1))`

  • The slope of the normal to the cirlce x^(2)+y^(2)=a^(2) at the point (x_(1),y_(1)) is -

    A
    `(x_(1))/(y_(1))`
    B
    `-(x_(1))/(y_(1))`
    C
    `-(y_(1))/(x_(1))`
    D
    `(y_(1))/(x_(1))`

  • The slop of the normal to the reactangular hyperbola xy=c^(2) point ( x_(1),y_(1)) is -

    A
    `-(x_(1))/(y_(1))`
    B
    `(x_(1))/(y_(1))`
    C
    `-(y_(1))/(x_(1))`
    D
    `(y_(1))/(x_(1))`

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