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The results obtained by applying the mat...

The results obtained by applying the mathematical form of the first law of thermodynamics for different process are given below. Identify the process (w=P-V work only): `DeltaU=0, q+w=0`

Text Solution

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According to the first law of thermodynamics, `Delta=q+w` . .[1]
(i) In the process , `DeltaU=0` U is a state function. So, in a cyclic process, its change is zero. So, from equation [1], q+w=0. thus, the given conditions indicate a cyclic process.
(ii) again in isothermal process, the change in internal energy for the ideal gas is zero. thus according to equation [1], for isothermal change of ann ideal gas, q+w=0. thus, the given conditions indicate an isothermal change.
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Knowledge Check

  • The mathemeatical form of the first law of thermodynamics when q is the heat supplied and w the work done by the system is

    A
    `DeltaU=q+w`
    B
    `DeltaU=q-w`
    C
    `DeltaU=w-q`
    D
    `DeltaU=-q-w`
  • Statement I : In an isothermal process the whole heat energy supplied to the body is converted into internal energy. Statement II : According to the first law of thermodynamics Delta Q = Delta U + p Delta V .

    A
    Statement I is true, statement II is true, statement II is a correct explanation for statement I.
    B
    Statement I is true, statement II is true, statement II is not a correct explanation for statement I.
    C
    Statement I is true, statement II is false
    D
    Statement I is false, statement II is true.
  • A parallel plate capacitor of plate area A and plate separation d is charged to potential V and then the battery is disconnected. A slab of dielectric constant k is then inserted, between the plates of the capacitors so as to fill the space between the plates. If Q, E and W denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted) and work done on the system in question in the process of inserting the slab, then state incorrect

    A
    `Q=(epsilon_0AV)/d`
    B
    `W=(epsilon_0AV^2)/(2kd)`
    C
    `E=V/(kd)`
    D
    `W=(epsilon_0AV^2)/(2d)(1/1-1)`
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