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Sn(II) is a reducing agent but Pb(II) is...

Sn(II) is a reducing agent but Pb(II) is not-why?

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Because of inert pair effect, both tin and lead show two oxidation states of +2 and +4. But this effect is more prominent in case of Pb than in Sn and consequently, +2 oxidation state of Sn is less stable than its +4 oxidation state. Therefore, Sn(II) acts as a reducing agent and gets converted to the more stable Sn(IV) by losing two electrons. In contrast, the +2 oxidation state of Pb is more stable than its +4 oxidation state due to prominent inert pair effect. Therefore, Pb(II) does not lose electrons easily and does not act as a reducing agent.
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Knowledge Check

  • A poisonous reducing agent is

    A
    `H_2`
    B
    CO
    C
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    D
    `HI`

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