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Hydride of boron occurs as B2H6 but B2Cl...

Hydride of boron occurs as `B_2H_6` but `B_2Cl_6` does not exist. This is because-

A

`p pi - d pi` back bonding is possible in `B_2H_6` but not in `B_2Cl_6`

B

boron and hydrogen have almost equal values of electronegativity

C

boron and chlorine have almost equal atomic sizes

D

small hydrogen atoms can easily fit in between boron atoms but large chlorine atoms do not.

Text Solution

Verified by Experts

The correct Answer is:
A
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