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The initial concentration of the reactan...

The initial concentration of the reactant in a zero order reaction is `1.386 "mol.L"^(-1)` The half-life of the reaction is 20s. Calculate:
the rate constant

Text Solution

Verified by Experts

Half -life of a zero order reaction , `t_(1//2)=([A]_(0))/(2k)`
Given : `t_(1//2)=20s and [A]_(0)=1.386"mol. L"^(-1)`
`therefore=([A]_(0))/(2t_(1//2))=(1.386xx"mol.L"^(-1))/(2xx20s)=0.0346"mol.L"^(-1).s^(-1)`
`therefore` The rate constant of the reaction `=0.0346"mol.L"^(-1).s^(-1)`
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Knowledge Check

  • When initial concentration of the reactant is doubled, the half-life period of a zero order reaction -

    A
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