Home
Class 12
CHEMISTRY
The rate constant of a chemical reaction...

The rate constant of a chemical reaction at 600K is `1.6xx10^(-5)s^(-1)` . The activation energy of the reaction is `209"kJ.mol"^(-1)` . Calculate its rate constant at 700K.

Text Solution

Verified by Experts

We know , `log.(k_(2))/(k_(1))=(E_(a))/(2.303R)((T_(2)-T_(1))/(T_(1)-T_(2)))(T_(2)gtT_(1))`
Given, `T_(1)=600K,k_(1)=1.6xx10^(-5)s^(-1),T_(2)=700K,k_(2)=?`
`thereforelog.(k_(2))/(1.6xx10^(-5))=(209xx10^(3))/(2.303xx8.314)((700-600)/(600xx700))`
or, `log.(k_(2))/(1.6xx10^(-5))=2.598 " or, "k_(2)=6.35xx10^(-3)s^(-1)`
`therefore ` The rate constant at `700K=6.35xx10^(-3)s^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|55 Videos

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise QUESTION-ANSWER ZONE FOR BOARD EXAMINATION (VERY SHORT ANSWER TYPE)|35 Videos

  • BIOMOLECULES

    CHHAYA PUBLICATION|Exercise Practic Set 29|1 Videos

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise Practice Set 6|15 Videos

Similar Questions

Explore conceptually related problems

The unit of rate constant of a chemical reaction is L^2. mol^(-2).s^(-1) . Calculate order of the reaction.

The rate constant of decomposition of B is 4.8xx10^(3)s^(-1) " at "15^(@)C . If the activation energy of the reaction is 80 kJ.mol , at what temperature will the rate constant of the reaction be 1.5xx10^(4)s^(-1) ?

Knowledge Check

  • The rate of a reaction at 37^(@)C is twice the rate of the reaction at 27^(@)C . The activation energy (kJ.mol^(-1)) of the reaction is -

    A
    `48.2`
    B
    `37.9`
    C
    `62.4`
    D
    `53.6`

    • Similar Questions

    Explore conceptually related problems

    First order rate constant for the decomposition of ethyl iodide, C_(2)H_(5)I(g)rarrC_(2)H_(4)(g)+HI(g) at 600K is 1.60xx10^(-5)s^(-1) . Its activation energy is 209kJ."mol"^(-1) . Calculate rate constant of the reaction at 700K.

    The rate constant of a reaction is 1.8xx10^3 min^(-1) . What is the order of the reaction?

    The rate constant of a first order reaction is 2.31xx10^(-3)s^(-1) Calculate the half-life period of the activation energy of the reaction.

    The rate constant of a reaction at 200k is 0.1 times its value at TK . If the energy of activation of the reaction is 7.65"kJ.mol"^(-1) , find the value of 'T'?

    The rate constant of a reaction is 1.5xx10^(-3)"dm"^(3)."mol"^(-1).s^(-1). Determine its order .

    The rate constant of a first order reaction follows the equation logk(s^(-1))=22.3-(12.16xx10^(3))/(T)K Find the activation energy of the reaction.

    The unit of rate constant of a reaction is ("mol")^(-1//2). ("dm")^(3//2).s^(-1) . Determine the order of the reaction.

    Home
    Profile