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In the reaction 3Xrarr2Y+Z , the rate o...

In the reaction `3Xrarr2Y+Z` , the rate of disappearance of X at a given time is `0.072"mol.L"^(-1).s^(-1)` . Calculate the rate of formation of Y and that of Z at the same time ?

Text Solution

Verified by Experts

In this reaction, `-(1)/(3)(d[X])/(dt)=(1)/(2)(d[Y])/(dt)=(d[Z])/(dt)`
Here, `-(d[X])/(dt)=0.072"mol.L"^(-1).s^(-1)`
`therefore(d[Y])/(dt)=2xx(-(1)/(3)(d[X])/(dt))=(2)/(3)xx0.072`
`" " =0.048"mol.L"^(-1).s^(-1)`
Rate of formation of `Y=0.048"mol.L"^(-1).s^(-1)`
`therefore` Rate of formation of
`Z=(d[Z])/(dt)=-(1)/(3)(d[X])/(dt)=(1)/(3)xx0.072`
`" " =0.024"mol.L"^(-1).s^(-1)`
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  • At a particular time , in the reaction aA+bBrarrcD , if the rate of disappearance of B is thrice that of A and the rate of formation of D is twice the rate of disappearance of A , then the ratio between a, b and c will be -

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