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The rate constant for a first order reac...

The rate constant for a first order reaction is `60s^(-1)` How much time will it take to reduce the initial concentration of the reactant to its `(1)/(10)` th value?

Text Solution

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For a first order reaction , the integrated rate equation is
`t=(2.303)/(k)log.([A]_(0))/([A])`
We have to calculate t, when `[A]=([A]_(0))/(10)` . putting the values of [A] and k into the above equation , we get
`t=(2.303)/(60)log.([A]_(0))/(([A])/(10))=0.0457s`
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