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H(2)O , H(2)S,H(2)Se, H(2)Te (decreasing...

`H_(2)O , H_(2)S,H_(2)Se, H_(2)Te` (decreasing boiling point)

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Explore conceptually related problems

H_(2)O,H_(2)S,H_(2)Te,H_(2)Se ( decreasing bond angle)

Arrange the compounds as per their increasing order of the said property. H_2O , H_2S , H_2Se , H_2Te . (boiling point)

Out of H_2SO_4 , H_2S , H_2Se and H_2Te the one with the highest boiling point is:

Arrage H_(2)S,H_(2)O and H_(2)Se in the order of increasing bond angle .

Equal volumes of H_(2)S & SO_(2) react at NTP to form H_(2)O and S. 2H_(2)S+SO_(2) to 2H_(2)O+3S . In this reaction, I. H_(2)S is the limiting reactant. II. SO_(2) is the limiting reactant. III. Sulphur formed is three times of SO_(2) reacted IV. sulphur formed is 1.5 times of H_(2)S reacted. Select the correct statements(s).

(i) Which of H_(2)O or H_(2)S molecules has a greater bond angle? Explain. (ii) Between o-nitrophenol and p-nitrophenol, which one has a greater boiling point? Explain.

N_(2)H_(4) and H_(2)O_(2) show similarity in

H_(2)S and H_(2) cannot be dried by passing it through conc. H_(2)SO_(4) - why?

Explain why in the laboratory preparation of H_(2)O_(2) : dilute H_(2)SO_(4) is used instead of concentrated H_(2)SO_(4) ,

How is H_(2)O_(2) preserved in the laboratory?

Knowledge Check

  • Equal volumes of H_(2)S & SO_(2) react at NTP to form H_(2)O and S. 2H_(2)S+SO_(2) to 2H_(2)O+3S . In this reaction, I. H_(2)S is the limiting reactant. II. SO_(2) is the limiting reactant. III. Sulphur formed is three times of SO_(2) reacted IV. sulphur formed is 1.5 times of H_(2)S reacted. Select the correct statements(s).

    A
    all except I
    B
    all except II
    C
    all except I, III
    D
    all except II, IV