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Using crystal field theory, draw energy level diagram, write electronic configuration of central metal atom/ion, determine magnetic moment value in the following :
`[CoF_(6)]^(3-),[Co(H_(2)O)_(6)]^(2+),[Co(CN)_(6)]^(3-)`

Text Solution

Verified by Experts

`[CoF_(6)]^(3-)`:

No. of unpaired electron = 4,
`therefore mu=sqrt(n(n+2))=sqrt(4(4+2))=sqrt(24)=4.9BM`
`[Co(H_(2)O)_(6)]^(2+):`

No. of unpaired electrons = 3,
`therefore mu=sqrt(3(3+2))=sqrt(15)=3.87BM`
`[Co(CN)_(6)]^(3-),`

No. of unpaired electron = 0,
`therefore mu=sqrt(n(n+2))=sqrt(0(0+2))=0`
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