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On treatment of 100 mL of 0.1 M solution...

On treatment of 100 mL of 0.1 M solution of `CoCl_3.6H_2O` with excess `AgNO_3, 1.2 xx 10^(22)` ions are precipitated . The complex is -

A

`[Co(H_2O)_3Cl_3].3H_2O`

B

`[Co(H_2O)_6]Cl_3`

C

`[Co(H_2O)_5Cl]Cl_2.H_2O`

D

`[Co(H_2O)_4Cl_2]Cl.2H_2O`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • On treatment of 100 mL of 0.1(M) solution of CoCl_(3).6H_(2)O with excess AgNO_(3),1.2xx10^(22) ions are precipitated. The complex is -

    A
    `[Co(H_(2)O)_(6)]Cl_(3)`
    B
    `[Co(H_(2)O)_(5)Cl]Cl_(2).H_(2)O`
    C
    `[Co(H_(2)O)_(4)Cl_(2)]Cl.2H_(2)O`
    D
    `[Co(H_(2)O)_(3)Cl_(3)].3H_(2)O`

  • We have 100 ml 0.1 M KCL solution. To make it 0.2 M,

    A
    evaporate 50 ml `H_2O`
    B
    evaporate 50 ml solution
    C
    add 0.1 mol KCL
    D
    add 0.01 mol KCL

  • When 1 mole CrCl_(3).6H_(2)O is treated with excess of AgNO_(3), 3 mol AgCl are obtained. Formula of the complex :

    A
    `[CrCl_(3)(H_(2)O)_(3)].3H_(2)O`
    B
    `[CrCl_(2)(H_(2)O)_(4)]Cl. 2H_(2)O`
    C
    `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
    D
    `[Cr(H_(2)O)_(6)]Cl_(3)`

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