The two vectors vecA and vecB are drawn ...

The two vectors `vecA` and `vecB` are drawn from a common point and `vecC = vecA + vecB`. In column- I are given the conditions regarding the magnitudes of `vecA, vecB and vecC` as A, B, C respectively. Column- II gives the angle between the vectors `vecA and vecB`. Match them.

Text Solution

Verified by Experts

The correct Answer is:

`a to r; b to p; c to q,s; d to p`

(a) `A^(2) + B^(2) = C^(2) rArr theta = 90^(@)`
(b) `A^(2) + B^(2) gt C^(2) rArr theta = 90^(@)`
`A^(2) + B^(2) lt C^(2) rArr theta = 90^(@)`
(d) `A^(2) = B^(2) = C^(2) rArr theta = 120^(@) rArr theta gt 90^(@)`

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The two vectors vecA and vecB are drawn from a common point and vecC=vecA+vecB . Then, the angle between vecA and vecB is

`90^(@)` if `C^(2)gtA^(2)+B^(2)`

greater than `90^(@)` if `C^(2)ltA^(2)+B^(2)`

greater than `90^(@)` if `C^(2)gtA^(2)+B^(2)`

less than `90^(@)` if `C^(2)gtA^(2)+B^(2)`

The magnitudes of vectors vecA,vecB and vecC are 3,4 and 5 units respectively. If vecA+vecB= vecC , the angle between vecA and vecB is

`(pi)/2`

`cos^(-1)(0.6)`

`tan^(-1)(7/5)`

`(pi)/4`

A magnitude of vector vecA,vecB and vecC are respectively 12, 5 and 13 units and vecA+vecB=vecC then the angle between vecA and vecB is

`0`

`pi`

`pi//2`

`pi//4`