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If A = null set, then the no. of element...

If A = null set, then the no. of elements in `P(P(P(A)))` where `P(A)` denotes the power set of A is -

A

1

B

2

C

4

D

0

Text Solution

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The correct Answer is:
To solve the problem, we need to find the number of elements in \( P(P(P(A))) \) where \( A \) is a null set (or empty set). ### Step-by-Step Solution: 1. **Identify the Set A**: \[ A = \emptyset \] The null set (or empty set) has no elements. **Hint**: Remember that the empty set is denoted by \( \emptyset \) or \( \{\} \). 2. **Find the Power Set of A**: The power set \( P(A) \) is the set of all subsets of \( A \). Since \( A \) has no elements, the only subset of \( A \) is the empty set itself. \[ P(A) = \{ \emptyset \} \] Thus, \( P(A) \) contains 1 element. **Hint**: The power set of a set with \( n \) elements has \( 2^n \) elements. For the empty set, \( n = 0 \), so \( 2^0 = 1 \). 3. **Find the Power Set of P(A)**: Now we need to find \( P(P(A)) \). Since \( P(A) = \{ \emptyset \} \), we find the power set of this set. The subsets of \( P(A) \) are: - The empty set \( \emptyset \) - The set containing the empty set \( \{ \emptyset \} \) Therefore, \[ P(P(A)) = \{ \emptyset, \{ \emptyset \} \} \] Thus, \( P(P(A)) \) contains 2 elements. **Hint**: Again, use the formula for the power set. Since \( P(A) \) has 1 element, \( P(P(A)) \) will have \( 2^1 = 2 \) elements. 4. **Find the Power Set of P(P(A))**: Next, we need to find \( P(P(P(A))) \). Since \( P(P(A)) = \{ \emptyset, \{ \emptyset \} \} \), we find the power set of this set. The subsets of \( P(P(A)) \) are: - The empty set \( \emptyset \) - The set containing the empty set \( \{ \emptyset \} \) - The set containing the set \( \{ \emptyset \} \) \( \{ \{ \emptyset \} \} \) - The set containing both \( \emptyset \) and \( \{ \emptyset \} \) \( \{ \emptyset, \{ \emptyset \} \} \) Therefore, \[ P(P(P(A))) = \{ \emptyset, \{ \emptyset \}, \{ \{ \emptyset \} \}, \{ \emptyset, \{ \emptyset \} \} \} \] Thus, \( P(P(P(A))) \) contains 4 elements. **Hint**: For a set with 2 elements, the power set will have \( 2^2 = 4 \) elements. 5. **Conclusion**: The number of elements in \( P(P(P(A))) \) is 4. **Final Answer**: 4

To solve the problem, we need to find the number of elements in \( P(P(P(A))) \) where \( A \) is a null set (or empty set). ### Step-by-Step Solution: 1. **Identify the Set A**: \[ A = \emptyset \] ...
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If A is the null set, find the number of elements in the power set P(P(A)) .

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Knowledge Check

  • Which one of the following statement is correct? where P(A) denotes the power set of A.

    A
    ` A uu P (A) = A`
    B
    ` A nn P(A) = A `
    C
    ` A- P (A) = A `
    D
    ` P(A) - {A} = P(A) `
  • Which one of the following is correct? Here, P(A) denotes the power set of a set A.

    A
    A. `A cup P (A) =P(A)`
    B
    B. `A cap P (A)=A`
    C
    C. `A-P(A)=A`
    D
    D. `P(A)-(A)=P(A)`
  • If the set A contains 5 elements, then the number of elements in the power set P(A) is equal to

    A
    32
    B
    25
    C
    16
    D
    8
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