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Three randomly chosen nonnegative intege...

Three randomly chosen nonnegative integers `x , ya n dz` are found to satisfy the equation `x+y+z=10.` Then the probability that `z` is even, is: `5/(12)` (b) `1/2` (c) `6/(11)` (d) `(36)/(55)`

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  • The values of x, y, z for the equations 5x-y+4z=5, 2x+3y+5z=2, 5x-2y+6z=1 are

    A
    `x=3, y=3, z=-2`
    B
    `x=1, y=2, z=1`
    C
    `x=1, y=3, z=5`
    D
    `x=3, y=2, z=-1`
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