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The coefficient of viscosity (eta) of a ...

The coefficient of viscosity `(eta)` of a fluid moving steadily between two surface is given by the formula `(f) = etaA dV//dx` where `f` is the frictional force on the fluid, `A` is the area in the fluid, and `dV//dx` is velocity gradient inside the fluid at that area. The SI unit of viscosity is given as :

A

`kg m^(-1) s^(-1)`

B

`Nm^(-2) s`

C

Nil

D

Newtons

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To find the SI unit of viscosity (η), we start from the formula given: \[ F = \eta A \frac{dV}{dx} \] Where: - \( F \) is the frictional force, - \( \eta \) is the coefficient of viscosity, - \( A \) is the area, - \( \frac{dV}{dx} \) is the velocity gradient. ### Step 1: Rearranging the formula to solve for η We can rearrange the formula to isolate η: \[ \eta = \frac{F}{A \frac{dV}{dx}} \] ### Step 2: Identifying the units of each variable Next, we need to identify the SI units of each variable: - The unit of force \( F \) is Newton (N). - The unit of area \( A \) is square meters (m²). - The velocity gradient \( \frac{dV}{dx} \) has units of velocity per unit distance. The unit of velocity \( V \) is meters per second (m/s), and the unit of distance \( x \) is meters (m). Therefore, the unit of \( \frac{dV}{dx} \) is: \[ \frac{m/s}{m} = s^{-1} \] ### Step 3: Substituting the units into the equation for η Now we can substitute the units into the equation for η: \[ \text{Unit of } \eta = \frac{\text{Unit of } F}{\text{Unit of } A \times \text{Unit of } \frac{dV}{dx}} \] Substituting the units we identified: \[ \text{Unit of } \eta = \frac{N}{m^2 \cdot s^{-1}} \] ### Step 4: Converting Newton into base SI units Recall that 1 Newton (N) can be expressed in terms of base SI units: \[ 1 \, N = 1 \, \text{kg} \cdot \text{m/s}^2 \] Thus, we can rewrite the unit of η: \[ \text{Unit of } \eta = \frac{kg \cdot m/s^2}{m^2 \cdot s^{-1}} \] ### Step 5: Simplifying the units Now, we simplify the expression: \[ \text{Unit of } \eta = \frac{kg \cdot m}{s^2} \cdot \frac{s}{m^2} \] This simplifies to: \[ \text{Unit of } \eta = \frac{kg}{m \cdot s} \] ### Conclusion Thus, the SI unit of viscosity (η) is: \[ \text{Unit of } \eta = \text{kg} \cdot \text{m}^{-1} \cdot \text{s}^{-1} \]

To find the SI unit of viscosity (η), we start from the formula given: \[ F = \eta A \frac{dV}{dx} \] Where: - \( F \) is the frictional force, - \( \eta \) is the coefficient of viscosity, - \( A \) is the area, ...
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