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The relationship between energy E, of th...

The relationship between energy E, of the radiation with a wavelength 8000 Å and the energy of the radiation with a wavelength 16000 Å is

A

`E_(1) = 6E_(2)`

B

`E_(1) = 2E_(2)`

C

`E_(1) = 4E_(2)`

D

`E_(10 = 1//2E_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E = hv =(hc)/(lambda)`
`(E_(1))/(E_(2)) =(hc//lambda_(1))/(hc//lambda_(1)) = (lambda_(2))/(lambda_(1)) = (16000 Å)/(8000 Å) = 2`
`:. E_(1) = 2E_(2)`
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Knowledge Check

  • A light has a wavelength 6000Å. The energy of this light is

    A
    `5eV`
    B
    `2.07eV`
    C
    `1.07eV`
    D
    `0.207eV`

  • The energy of a photon of radiation having wavelength 300 nm is,

    A
    `6.63xx10^(29)J`
    B
    `6.63xx10^(-19)J`
    C
    `6.63xx10^(-28)J`
    D
    `6.63xx10^(-17)J`

  • The energy of a photon (in ev) of wavelength 5000 Å will be

    A
    2.48 ev
    B
    8.42 ev
    C
    zero
    D
    4.82 ev

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