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At low pressures, the van der waal's equ...

At low pressures, the van der waal's equation is written as
`[P + (a)/(V^(2))] V = RT`
The compressibility factor is then equal to

A

`(1 - (a)/(RTV))`

B

`(1- (RTV)/(a))`

C

`(1+ (a)/(RTV))`

D

`(1+ (RTV)/(a))`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P + (a)/(V^(2))) V = RT`
`PV + (a)/(V) = RT`
`(PV)/(RT) + (a)/(VRT) = 1`
`Z = 1 - (a)/(VRT)`
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Knowledge Check

  • In the van der Waals equation

    A
    `b` is the volume occupied by the gas molecules
    B
    `b` is four times the volume occupied by the gas molecules
    C
    `b` is the correction factor for intermolecular attraction
    D
    None of these

  • At low pressures (for 1 mole), the van der Waal's equation is written as [P+(a)/(V^(2))]V=RT The compressibility factor is then equal to :

    A
    `(1-(a)/(RTV))`
    B
    `(1-(RTV)/(a))`
    C
    `(1+(a)/(RTV))`
    D
    `(1+(RTV)/(a))`

  • At low pressure, the van der Waals equation is reduced to

    A
    `Z = (PV_m)/(RT) =1-(a)/(RTV_m)`
    B
    `Z = (PV_m)/(RT) = 1+(bP)/(RT)`
    C
    `PV_m = RT`
    D
    `Z=(PV_m)/(RT)=1- (a)/(RT)`

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