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The decomposition of NH(3) on finely div...

The decomposition of `NH_(3)` on finely divided platinum follows the rate expression
Rate `=(k_(1)[NH_(3)])/(1+k_(2)[NH_(3)])`
it is a first order reaction when concentration of `NH_(3)` is

A

very low

B

very high

C

moderate

D

never

Text Solution

Verified by Experts

The correct Answer is:
A
Rate `=(k_(1)[NH_(3)])/(1+k_(2)[NH_(3)])`
when `[NH_(3)]` is very low
`1+k_(2)[NH_(3)]~~1`
`therefore` Rate `=k_(1)[NH_(3)]`
Thus, the reaction becomes a first order reaction at low concentration.
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