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The general expression for rate constant...

The general expression for rate constant k for an nth order reaction
`k=1/((n-1)t)[1/([A]^(n-1))-1/([A]_(0)^(n-1))]` is

A

valid for zero order reaction

B

not valid for first order reaction

C

not valid for zero order reaction

D

not valid for negative/fractional order reaction

Text Solution

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The correct Answer is:
To determine the validity of the expression for the rate constant \( k \) for an nth order reaction, we can analyze the expression step by step. ### Step-by-Step Solution: 1. **Understanding the Expression**: The expression given for the rate constant \( k \) for an nth order reaction is: \[ k = \frac{1}{(n-1)t} \left( \frac{1}{[A]^{(n-1)}} - \frac{1}{[A_0]^{(n-1)}} \right) \] Here, \( [A] \) is the concentration at time \( t \), \( [A_0] \) is the initial concentration, and \( n \) is the order of the reaction. 2. **Checking for Zero Order Reaction**: For a zero-order reaction, \( n = 0 \): \[ k = \frac{1}{(0-1)t} \left( \frac{1}{[A]^{-1}} - \frac{1}{[A_0]^{-1}} \right) \] Simplifying this gives: \[ k = -\frac{1}{t} \left( [A] - [A_0] \right) \] Rearranging leads to the equation: \[ [A] = [A_0] - kt \] This is a valid expression for a zero-order reaction. 3. **Checking for First Order Reaction**: For a first-order reaction, \( n = 1 \): \[ k = \frac{1}{(1-1)t} \left( \frac{1}{[A]^{0}} - \frac{1}{[A_0]^{0}} \right) \] This simplifies to: \[ k = \frac{1}{0} \left( 1 - 1 \right) \] This results in an undefined expression (division by zero), indicating that the expression is not valid for first-order reactions. 4. **Checking for Fractional Order Reactions**: If \( n \) is a negative fraction, the expression can still be evaluated: \[ k = \frac{1}{(n-1)t} \left( \frac{1}{[A]^{(n-1)}} - \frac{1}{[A_0]^{(n-1)}} \right) \] This will yield a valid expression, as \( n-1 \) will not equal zero, and thus the expression remains defined. ### Conclusion: The expression for \( k \) is valid for zero-order reactions and for reactions with negative fractional orders. However, it is not valid for first-order reactions.
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The rate expression for an nth - order reaction (n != 1) is

Given that for a reaction of order n the integrated form of the rate equation is k=1/(t(n-1))[1/C_(n-1) -1/(C_0^(n-1))] where C_0 and C are the values of the reactant concentration at the start and after time t . What is the relationship between t_(3/4) and t_(½) ?

Knowledge Check

  • The general expression for half-life period of an nth order reaction (for n != 1) is

    A
    `t_(1//2)= (2^(n)-1)/((n-1)[A]_(0)^(n-1)k)`
    B
    `t_(1//2)= (2^(n-1)-1)/((n+1)[A]_(0)^(n-1)k)`
    C
    `t_(1//2)= (2^(n+1)+1)/((n+1)[A]_(0)^(n-1)k)`
    D
    `t_(1//2)= (2^(n-1)-1)/((n-1)[A]_(0)^(n-1)k)`
  • The general expression for half life period of an nth order reaction t_(1//2)=(2^(n-1)-1)/(k(n-1)a^(n-1)) is

    A
    valid for all reactions
    B
    not valid for fractional or negative order reactions
    C
    not valid for first order reactions
    D
    not valid for zero order reaction
  • Given that for a reaction of order n. the intergrated form of the rate equation is k= (1)/(t(n-1))[(1)/(C^(n-1))-(1)/(C_(0)^(n-1))] where C_(0) and C are the values after time t. What is the relationship between t_(3//4) and t_(1//2) where t_(3//4) is the time required for C to become 1//4C_(0)-

    A
    `t_(3//4) = t_(1//2)[2^(n-1) +1]`
    B
    `t_(3//4) =t_(1//2)[2^(n-1)-1]`
    C
    `t_(3//4) =t_(1//2) [2^(n+1) -1]`
    D
    `t_(3//4) =t_(1//2) [2^(n+1)+1]`
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