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Boron does not form B^(3+) ions because...

Boron does not form `B^(3+)` ions because

A

boron has small size and high ionization energy

B

boron has high electronegativity

C

boron has high charge density

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Because B has small size and high ionization energy which is not available from hydration of ion.
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Why boron does not form B^(3+) ion?

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Knowledge Check

  • Boron does not form B^(3+) ion, because:

    A
    Energy required to form `B^(3+)` ion is very high which will not be compensated by lattice enthalpies of hydration enthalpies of such ion.
    B
    Boron is a non-metal.
    C
    Boron is a metalloid.
    D
    None of the above.

  • Boron does not form B^(3+) ion, due to.

    A
    Energy required to form `B^(3+)` ion is very high which will not be compensated by lattice enthalpies or hydration enthalpies of such ion.
    B
    Boron is a non-metal
    C
    Boron is a metalloid
    D
    None of the above

  • Assertion:- Boron does not form N^(+3) ion. Reason:- Boron does not form compound in its ground state.

    A
    If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.
    B
    If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.
    C
    If Assertion is True but the Reason is False.
    D
    If both Assertion `&` Reason are False.

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    Aluminium forms [AIF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion. Explain.

    Explain the following : (i) Gallium has higher ionisation enthalpy than aluminium. (ii) Boron does not exists as B^(3+) ion. (iii) Aluminium forms [AlF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion. (iv) PbX_(2) is more stable than PbX_(4) . (v) Pb^(4+) acts as an oxidising agent but Sn^(2+) acts as a reducing agent. (vi) Electron gain enthalpy of chlorine is more negative as compared to fluorine. (vii) Tl(NO_(3))_(3) acts as an oxidising agent. (viii) Carbon shows catenation property but lead does not. (ix) BF_(3) does not hydrolyse completely (modified). (x) Why does the elemnet silicon, not form a graphite like structure whereas carbon does.

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    Aluminum forms [AIF_(6)]^(3-) but boron does not form [BF_(6)]^(3-) because

    Assertion (A) : Al forms [AlF_(6)]^(3-) ions but B does not form [BF_(6)]^(3-) ions. Reason (R) : B does not react with F_(2) .

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