A current carrying conductor placed in a magnetic field experiences maximum force when angle between current and magnetic field is :

Options

A. `3pi//4`
B. `pi//2`
C. `pi//4`
D. Zero

Explanation

To find the angle at which a current-carrying conductor experiences maximum force in a magnetic field, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Force on a Current-Carrying Conductor**:
The force \( F \) experienced by a current-carrying conductor in a magnetic field is given by the formula:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]
where:
- \( F \) = force on the conductor
- \( I \) = current flowing through the conductor
- \( L \) = length of the conductor in the magnetic field
- \( B \) = magnetic field strength
- \( \theta \) = angle between the direction of current and the magnetic field

2. **Identify the Condition for Maximum Force**:
To find the maximum force, we need to maximize the term \( \sin(\theta) \). The sine function reaches its maximum value of 1 when:
\[ \sin(\theta) = 1 \]

3. **Determine the Angle for Maximum Force**:
The angle \( \theta \) for which \( \sin(\theta) = 1 \) is:
\[ \theta = 90^\circ \quad \text{or} \quad \theta = \frac{\pi}{2} \text{ radians} \]

4. **Conclusion**:
Therefore, the angle between the current and the magnetic field at which the current-carrying conductor experiences maximum force is:
\[ \theta = 90^\circ \quad \text{or} \quad \theta = \frac{\pi}{2} \]

### Final Answer:
The angle between the current and the magnetic field for maximum force is \( 90^\circ \) or \( \frac{\pi}{2} \) radians.

---