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At a high pressure, the compressibility ...

At a high pressure, the compressibility factor (Z) of a real gas is usually greater than one. This can be explained from van der Waals equation by neglecting the value of:

A

b

B

a

C

Both a and b

D

V

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To solve the question regarding the compressibility factor (Z) of a real gas at high pressure using the van der Waals equation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Compressibility Factor (Z)**: The compressibility factor (Z) is defined as \( Z = \frac{PV}{nRT} \). For an ideal gas, Z is equal to 1. However, for real gases, especially at high pressures, Z can be greater than 1. 2. **Recall the van der Waals Equation**: The van der Waals equation for one mole of a gas is given by: \[ \left(P + \frac{a}{V^2}\right)(V - b) = RT \] where \( a \) and \( b \) are constants specific to the gas, representing intermolecular forces and the volume occupied by gas molecules, respectively. 3. **Analyze Conditions at High Pressure**: At high pressure, the volume (V) of the gas decreases significantly because pressure and volume are inversely related (Boyle's Law). Therefore, we can conclude that V becomes very small. 4. **Neglecting Terms in the van der Waals Equation**: Since V is small at high pressure, the term \( \frac{a}{V^2} \) becomes very large. However, we are interested in what we can neglect. As V decreases, the term \( \frac{a}{V^2} \) becomes significant, but the volume correction term \( b \) (which accounts for the volume occupied by the gas molecules) becomes less significant compared to the pressure correction term \( \frac{a}{V^2} \). 5. **Final Form of the Equation**: Thus, we can neglect the term \( \frac{a}{V^2} \) in the van der Waals equation when considering high pressures. The modified equation simplifies to: \[ P(V - b) = RT \] 6. **Conclusion**: Therefore, the value that we neglect in the van der Waals equation at high pressure is \( \frac{a}{V^2} \) or simply \( a \). ### Answer: The correct answer is that we neglect the value of \( \frac{a}{V^2} \) in the van der Waals equation. ---

To solve the question regarding the compressibility factor (Z) of a real gas at high pressure using the van der Waals equation, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Compressibility Factor (Z)**: The compressibility factor (Z) is defined as \( Z = \frac{PV}{nRT} \). For an ideal gas, Z is equal to 1. However, for real gases, especially at high pressures, Z can be greater than 1. 2. **Recall the van der Waals Equation**: ...
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Knowledge Check

  • At very high pressure, the compressibility factor of one mole of a gas is given by :

    A
    `1+(Pb)/(RT)`
    B
    `(Pb)/(RT)`
    C
    `1-(Pb)/(RT)`
    D
    `1-(b)/((VRT))`
  • At very high pressures, the compressibility factor of one mole of a gas is given by:

    A
    `1+(pb)/(RT)`
    B
    `(Pb)/(RT)`
    C
    `1-(pb)/(RT)`
    D
    `1-b/((VRT))`
  • At high pressure, the compressibility factor for one mole of van der waals gas will be

    A
    1 + `frac{b}{RT}`
    B
    1 - `frac{Pb}{RT}`
    C
    1 + `frac{Pb}{RT}`
    D
    1 + `frac{a}{VRT}`
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