The heat of neutralization of any strong acid and a strong base is nearly equal to :

Options

A. `-75.3 kJ`
B. `+57.3 kJ`
C. `-57.3 kJ`
D. `+57.3 kJ`

Explanation

To solve the problem regarding the heat of neutralization of any strong acid and a strong base, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Neutralization**:
- Neutralization is a chemical reaction between an acid and a base, resulting in the formation of water and a salt. For strong acids and strong bases, this reaction goes to completion.

2. **Identifying the Reaction**:
- Consider a strong acid (HX) and a strong base (BOH). The dissociation of these compounds in water can be represented as:
- HX → H⁺ + X⁻ (strong acid)
- BOH → B⁺ + OH⁻ (strong base)

3. **Combining Ions**:
- When the H⁺ ions from the acid react with the OH⁻ ions from the base, they form water:
- H⁺ + OH⁻ → H₂O

4. **Heat of Neutralization**:
- The heat of neutralization (ΔH) for this reaction is the energy change that occurs when one equivalent of an acid reacts with one equivalent of a base. For strong acids and strong bases, this value is approximately constant.

5. **Value of ΔH**:
- The heat of neutralization for the reaction between a strong acid and a strong base is typically around -57.3 kJ/mol. This negative sign indicates that the reaction is exothermic, meaning heat is released during the reaction.

6. **Conclusion**:
- Therefore, the heat of neutralization of any strong acid and a strong base is nearly equal to -57.3 kJ.

### Final Answer:
The heat of neutralization of any strong acid and a strong base is nearly equal to **-57.3 kJ**.

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